x^2-2x+41=15

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Solution for x^2-2x+41=15 equation:


Simplifying
x2 + -2x + 41 = 15

Reorder the terms:
41 + -2x + x2 = 15

Solving
41 + -2x + x2 = 15

Solving for variable 'x'.

Reorder the terms:
41 + -15 + -2x + x2 = 15 + -15

Combine like terms: 41 + -15 = 26
26 + -2x + x2 = 15 + -15

Combine like terms: 15 + -15 = 0
26 + -2x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-26' to each side of the equation.
26 + -2x + -26 + x2 = 0 + -26

Reorder the terms:
26 + -26 + -2x + x2 = 0 + -26

Combine like terms: 26 + -26 = 0
0 + -2x + x2 = 0 + -26
-2x + x2 = 0 + -26

Combine like terms: 0 + -26 = -26
-2x + x2 = -26

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -26 + 1

Reorder the terms:
1 + -2x + x2 = -26 + 1

Combine like terms: -26 + 1 = -25
1 + -2x + x2 = -25

Factor a perfect square on the left side:
(x + -1)(x + -1) = -25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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